Integrand size = 24, antiderivative size = 250 \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\frac {c^2 x}{e^4}+\frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c d^2-7 b d e-5 a e^2\right ) \left (c d^2-b d e+a e^2\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\left (29 c^2 d^4-2 c d^2 e (11 b d-a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) x}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {\left (35 c^2 d^4-2 c d^2 e (5 b d+a e)-e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{16 d^{7/2} e^{9/2}} \]
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Time = 0.34 (sec) , antiderivative size = 250, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {1171, 1828, 396, 211} \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=-\frac {\arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right ) \left (-e^2 \left (5 a^2 e^2+2 a b d e+b^2 d^2\right )-2 c d^2 e (a e+5 b d)+35 c^2 d^4\right )}{16 d^{7/2} e^{9/2}}+\frac {x \left (e^2 \left (5 a^2 e^2+2 a b d e+b^2 d^2\right )-2 c d^2 e (11 b d-a e)+29 c^2 d^4\right )}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {x \left (-5 a e^2-7 b d e+19 c d^2\right ) \left (a e^2-b d e+c d^2\right )}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {x \left (a e^2-b d e+c d^2\right )^2}{6 d e^4 \left (d+e x^2\right )^3}+\frac {c^2 x}{e^4} \]
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Rule 211
Rule 396
Rule 1171
Rule 1828
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\int \frac {\frac {c^2 d^4-2 c d^2 e (b d-a e)+e^2 \left (b^2 d^2-2 a b d e-5 a^2 e^2\right )}{e^4}-\frac {6 d \left (c^2 d^2+b^2 e^2-2 c e (b d-a e)\right ) x^2}{e^3}+\frac {6 c d (c d-2 b e) x^4}{e^2}-\frac {6 c^2 d x^6}{e}}{\left (d+e x^2\right )^3} \, dx}{6 d} \\ & = \frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c d^2-7 b d e-5 a e^2\right ) \left (c d^2-b d e+a e^2\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\int \frac {\frac {3 \left (5 c^2 d^4-2 c d^2 e (3 b d-a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right )}{e^4}-\frac {48 c d^2 (c d-b e) x^2}{e^3}+\frac {24 c^2 d^2 x^4}{e^2}}{\left (d+e x^2\right )^2} \, dx}{24 d^2} \\ & = \frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c d^2-7 b d e-5 a e^2\right ) \left (c d^2-b d e+a e^2\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\left (29 c^2 d^4-2 c d^2 e (11 b d-a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) x}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {\int \frac {\frac {3 \left (19 c^2 d^4-2 c d^2 e (5 b d+a e)-e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right )}{e^4}-\frac {48 c^2 d^3 x^2}{e^3}}{d+e x^2} \, dx}{48 d^3} \\ & = \frac {c^2 x}{e^4}+\frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c d^2-7 b d e-5 a e^2\right ) \left (c d^2-b d e+a e^2\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\left (29 c^2 d^4-2 c d^2 e (11 b d-a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) x}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {\left (35 c^2 d^4-2 c d^2 e (5 b d+a e)-e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) \int \frac {1}{d+e x^2} \, dx}{16 d^3 e^4} \\ & = \frac {c^2 x}{e^4}+\frac {\left (c d^2-b d e+a e^2\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c d^2-7 b d e-5 a e^2\right ) \left (c d^2-b d e+a e^2\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\left (29 c^2 d^4-2 c d^2 e (11 b d-a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) x}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {\left (35 c^2 d^4-2 c d^2 e (5 b d+a e)-e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) \tan ^{-1}\left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{16 d^{7/2} e^{9/2}} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 267, normalized size of antiderivative = 1.07 \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\frac {c^2 x}{e^4}+\frac {\left (c d^2+e (-b d+a e)\right )^2 x}{6 d e^4 \left (d+e x^2\right )^3}-\frac {\left (19 c^2 d^4+2 c d^2 e (-13 b d+7 a e)+e^2 \left (7 b^2 d^2-2 a b d e-5 a^2 e^2\right )\right ) x}{24 d^2 e^4 \left (d+e x^2\right )^2}+\frac {\left (29 c^2 d^4+2 c d^2 e (-11 b d+a e)+e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) x}{16 d^3 e^4 \left (d+e x^2\right )}-\frac {\left (35 c^2 d^4-2 c d^2 e (5 b d+a e)-e^2 \left (b^2 d^2+2 a b d e+5 a^2 e^2\right )\right ) \arctan \left (\frac {\sqrt {e} x}{\sqrt {d}}\right )}{16 d^{7/2} e^{9/2}} \]
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Time = 0.26 (sec) , antiderivative size = 285, normalized size of antiderivative = 1.14
method | result | size |
default | \(\frac {c^{2} x}{e^{4}}+\frac {\frac {\frac {e^{2} \left (5 a^{2} e^{4}+2 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}-22 b c \,d^{3} e +29 c^{2} d^{4}\right ) x^{5}}{16 d^{3}}+\frac {e \left (5 a^{2} e^{4}+2 a b d \,e^{3}-2 a c \,d^{2} e^{2}-b^{2} d^{2} e^{2}-10 b c \,d^{3} e +17 c^{2} d^{4}\right ) x^{3}}{6 d^{2}}+\frac {\left (11 a^{2} e^{4}-2 a b d \,e^{3}-2 a c \,d^{2} e^{2}-b^{2} d^{2} e^{2}-10 b c \,d^{3} e +19 c^{2} d^{4}\right ) x}{16 d}}{\left (e \,x^{2}+d \right )^{3}}+\frac {\left (5 a^{2} e^{4}+2 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}+10 b c \,d^{3} e -35 c^{2} d^{4}\right ) \arctan \left (\frac {e x}{\sqrt {e d}}\right )}{16 d^{3} \sqrt {e d}}}{e^{4}}\) | \(285\) |
risch | \(\frac {c^{2} x}{e^{4}}+\frac {\frac {e^{2} \left (5 a^{2} e^{4}+2 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}-22 b c \,d^{3} e +29 c^{2} d^{4}\right ) x^{5}}{16 d^{3}}+\frac {e \left (5 a^{2} e^{4}+2 a b d \,e^{3}-2 a c \,d^{2} e^{2}-b^{2} d^{2} e^{2}-10 b c \,d^{3} e +17 c^{2} d^{4}\right ) x^{3}}{6 d^{2}}+\frac {\left (11 a^{2} e^{4}-2 a b d \,e^{3}-2 a c \,d^{2} e^{2}-b^{2} d^{2} e^{2}-10 b c \,d^{3} e +19 c^{2} d^{4}\right ) x}{16 d}}{e^{4} \left (e \,x^{2}+d \right )^{3}}-\frac {5 \ln \left (e x +\sqrt {-e d}\right ) a^{2}}{32 \sqrt {-e d}\, d^{3}}-\frac {\ln \left (e x +\sqrt {-e d}\right ) a b}{16 e \sqrt {-e d}\, d^{2}}-\frac {\ln \left (e x +\sqrt {-e d}\right ) a c}{16 e^{2} \sqrt {-e d}\, d}-\frac {\ln \left (e x +\sqrt {-e d}\right ) b^{2}}{32 e^{2} \sqrt {-e d}\, d}-\frac {5 \ln \left (e x +\sqrt {-e d}\right ) b c}{16 e^{3} \sqrt {-e d}}+\frac {35 d \ln \left (e x +\sqrt {-e d}\right ) c^{2}}{32 e^{4} \sqrt {-e d}}+\frac {5 \ln \left (-e x +\sqrt {-e d}\right ) a^{2}}{32 \sqrt {-e d}\, d^{3}}+\frac {\ln \left (-e x +\sqrt {-e d}\right ) a b}{16 e \sqrt {-e d}\, d^{2}}+\frac {\ln \left (-e x +\sqrt {-e d}\right ) a c}{16 e^{2} \sqrt {-e d}\, d}+\frac {\ln \left (-e x +\sqrt {-e d}\right ) b^{2}}{32 e^{2} \sqrt {-e d}\, d}+\frac {5 \ln \left (-e x +\sqrt {-e d}\right ) b c}{16 e^{3} \sqrt {-e d}}-\frac {35 d \ln \left (-e x +\sqrt {-e d}\right ) c^{2}}{32 e^{4} \sqrt {-e d}}\) | \(531\) |
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Leaf count of result is larger than twice the leaf count of optimal. 498 vs. \(2 (234) = 468\).
Time = 0.27 (sec) , antiderivative size = 1016, normalized size of antiderivative = 4.06 \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\left [\frac {96 \, c^{2} d^{4} e^{4} x^{7} + 6 \, {\left (77 \, c^{2} d^{5} e^{3} - 22 \, b c d^{4} e^{4} + 2 \, a b d^{2} e^{6} + 5 \, a^{2} d e^{7} + {\left (b^{2} + 2 \, a c\right )} d^{3} e^{5}\right )} x^{5} + 16 \, {\left (35 \, c^{2} d^{6} e^{2} - 10 \, b c d^{5} e^{3} + 2 \, a b d^{3} e^{5} + 5 \, a^{2} d^{2} e^{6} - {\left (b^{2} + 2 \, a c\right )} d^{4} e^{4}\right )} x^{3} + 3 \, {\left (35 \, c^{2} d^{7} - 10 \, b c d^{6} e - 2 \, a b d^{4} e^{3} - 5 \, a^{2} d^{3} e^{4} - {\left (b^{2} + 2 \, a c\right )} d^{5} e^{2} + {\left (35 \, c^{2} d^{4} e^{3} - 10 \, b c d^{3} e^{4} - 2 \, a b d e^{6} - 5 \, a^{2} e^{7} - {\left (b^{2} + 2 \, a c\right )} d^{2} e^{5}\right )} x^{6} + 3 \, {\left (35 \, c^{2} d^{5} e^{2} - 10 \, b c d^{4} e^{3} - 2 \, a b d^{2} e^{5} - 5 \, a^{2} d e^{6} - {\left (b^{2} + 2 \, a c\right )} d^{3} e^{4}\right )} x^{4} + 3 \, {\left (35 \, c^{2} d^{6} e - 10 \, b c d^{5} e^{2} - 2 \, a b d^{3} e^{4} - 5 \, a^{2} d^{2} e^{5} - {\left (b^{2} + 2 \, a c\right )} d^{4} e^{3}\right )} x^{2}\right )} \sqrt {-d e} \log \left (\frac {e x^{2} - 2 \, \sqrt {-d e} x - d}{e x^{2} + d}\right ) + 6 \, {\left (35 \, c^{2} d^{7} e - 10 \, b c d^{6} e^{2} - 2 \, a b d^{4} e^{4} + 11 \, a^{2} d^{3} e^{5} - {\left (b^{2} + 2 \, a c\right )} d^{5} e^{3}\right )} x}{96 \, {\left (d^{4} e^{8} x^{6} + 3 \, d^{5} e^{7} x^{4} + 3 \, d^{6} e^{6} x^{2} + d^{7} e^{5}\right )}}, \frac {48 \, c^{2} d^{4} e^{4} x^{7} + 3 \, {\left (77 \, c^{2} d^{5} e^{3} - 22 \, b c d^{4} e^{4} + 2 \, a b d^{2} e^{6} + 5 \, a^{2} d e^{7} + {\left (b^{2} + 2 \, a c\right )} d^{3} e^{5}\right )} x^{5} + 8 \, {\left (35 \, c^{2} d^{6} e^{2} - 10 \, b c d^{5} e^{3} + 2 \, a b d^{3} e^{5} + 5 \, a^{2} d^{2} e^{6} - {\left (b^{2} + 2 \, a c\right )} d^{4} e^{4}\right )} x^{3} - 3 \, {\left (35 \, c^{2} d^{7} - 10 \, b c d^{6} e - 2 \, a b d^{4} e^{3} - 5 \, a^{2} d^{3} e^{4} - {\left (b^{2} + 2 \, a c\right )} d^{5} e^{2} + {\left (35 \, c^{2} d^{4} e^{3} - 10 \, b c d^{3} e^{4} - 2 \, a b d e^{6} - 5 \, a^{2} e^{7} - {\left (b^{2} + 2 \, a c\right )} d^{2} e^{5}\right )} x^{6} + 3 \, {\left (35 \, c^{2} d^{5} e^{2} - 10 \, b c d^{4} e^{3} - 2 \, a b d^{2} e^{5} - 5 \, a^{2} d e^{6} - {\left (b^{2} + 2 \, a c\right )} d^{3} e^{4}\right )} x^{4} + 3 \, {\left (35 \, c^{2} d^{6} e - 10 \, b c d^{5} e^{2} - 2 \, a b d^{3} e^{4} - 5 \, a^{2} d^{2} e^{5} - {\left (b^{2} + 2 \, a c\right )} d^{4} e^{3}\right )} x^{2}\right )} \sqrt {d e} \arctan \left (\frac {\sqrt {d e} x}{d}\right ) + 3 \, {\left (35 \, c^{2} d^{7} e - 10 \, b c d^{6} e^{2} - 2 \, a b d^{4} e^{4} + 11 \, a^{2} d^{3} e^{5} - {\left (b^{2} + 2 \, a c\right )} d^{5} e^{3}\right )} x}{48 \, {\left (d^{4} e^{8} x^{6} + 3 \, d^{5} e^{7} x^{4} + 3 \, d^{6} e^{6} x^{2} + d^{7} e^{5}\right )}}\right ] \]
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Timed out. \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\text {Timed out} \]
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Exception generated. \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\text {Exception raised: ValueError} \]
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none
Time = 0.29 (sec) , antiderivative size = 320, normalized size of antiderivative = 1.28 \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\frac {c^{2} x}{e^{4}} - \frac {{\left (35 \, c^{2} d^{4} - 10 \, b c d^{3} e - b^{2} d^{2} e^{2} - 2 \, a c d^{2} e^{2} - 2 \, a b d e^{3} - 5 \, a^{2} e^{4}\right )} \arctan \left (\frac {e x}{\sqrt {d e}}\right )}{16 \, \sqrt {d e} d^{3} e^{4}} + \frac {87 \, c^{2} d^{4} e^{2} x^{5} - 66 \, b c d^{3} e^{3} x^{5} + 3 \, b^{2} d^{2} e^{4} x^{5} + 6 \, a c d^{2} e^{4} x^{5} + 6 \, a b d e^{5} x^{5} + 15 \, a^{2} e^{6} x^{5} + 136 \, c^{2} d^{5} e x^{3} - 80 \, b c d^{4} e^{2} x^{3} - 8 \, b^{2} d^{3} e^{3} x^{3} - 16 \, a c d^{3} e^{3} x^{3} + 16 \, a b d^{2} e^{4} x^{3} + 40 \, a^{2} d e^{5} x^{3} + 57 \, c^{2} d^{6} x - 30 \, b c d^{5} e x - 3 \, b^{2} d^{4} e^{2} x - 6 \, a c d^{4} e^{2} x - 6 \, a b d^{3} e^{3} x + 33 \, a^{2} d^{2} e^{4} x}{48 \, {\left (e x^{2} + d\right )}^{3} d^{3} e^{4}} \]
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Time = 7.72 (sec) , antiderivative size = 308, normalized size of antiderivative = 1.23 \[ \int \frac {\left (a+b x^2+c x^4\right )^2}{\left (d+e x^2\right )^4} \, dx=\frac {\frac {x^5\,\left (5\,a^2\,e^6+2\,a\,b\,d\,e^5+2\,a\,c\,d^2\,e^4+b^2\,d^2\,e^4-22\,b\,c\,d^3\,e^3+29\,c^2\,d^4\,e^2\right )}{16\,d^3}-\frac {x\,\left (-11\,a^2\,e^4+2\,a\,b\,d\,e^3+2\,a\,c\,d^2\,e^2+b^2\,d^2\,e^2+10\,b\,c\,d^3\,e-19\,c^2\,d^4\right )}{16\,d}+\frac {x^3\,\left (5\,a^2\,e^5+2\,a\,b\,d\,e^4-2\,a\,c\,d^2\,e^3-b^2\,d^2\,e^3-10\,b\,c\,d^3\,e^2+17\,c^2\,d^4\,e\right )}{6\,d^2}}{d^3\,e^4+3\,d^2\,e^5\,x^2+3\,d\,e^6\,x^4+e^7\,x^6}+\frac {c^2\,x}{e^4}+\frac {\mathrm {atan}\left (\frac {\sqrt {e}\,x}{\sqrt {d}}\right )\,\left (5\,a^2\,e^4+2\,a\,b\,d\,e^3+2\,a\,c\,d^2\,e^2+b^2\,d^2\,e^2+10\,b\,c\,d^3\,e-35\,c^2\,d^4\right )}{16\,d^{7/2}\,e^{9/2}} \]
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